Servlet技术:获取表单数据

2021-9-14

Servlet.java

package cn.xtnotes.servlet;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

public class Servlet4 extends HttpServlet {
	protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
		
		request.setCharacterEncoding("utf-8"); //设置请求数据编码
		response.setCharacterEncoding("utf-8");//设置响应数据编码
		String uname=request.getParameter("uname");
		String upwd=request.getParameter("upwd");
		PrintWriter pw=response.getWriter();
		if(uname!=null && upwd!=null) {
			if("123".equals(upwd)) {
				pw.print("用户"+uname+"登录成功!");
			}else {
				pw.print("密码错误");
			}
		}else {
			pw.print("不可为空");
		}
	}
	protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
	
		doGet(request, response);
	}

}

<!DOCTYPE html>
<html>
<head>
<meta charset="UTF-8">
<title>login</title>
</head>
<body>
<!-- action="" 提交的服务器地址   method:提交的方法  -->
<form action="http://127.0.0.1:8080/U8/Servlet4" method="post">
用户名: <input type="text" name="uname">
密码:   <input type="password" name="upwd">
<input type="submit">
</form>
</body>
</html>

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作者：Tin

链接：http://www.tinstu.com/469.html

文章版权归作者所有，未经允许请勿转载。

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